Could an optical clock at 1e-18 detect lifting it by 10 cm? How long w…

```python shift = zepto.clock_redshift(0.10) # fractional frequency shift for 10 cm print(f"Fractional frequency shift for 10 cm lift: {shift:.2e}") ```

shift = zepto.clock_redshift(0.10)  # fractional frequency shift for 10 cm
print(f"Fractional frequency shift for 10 cm lift: {shift:.2e}")

Fractional frequency shift for 10 cm lift: 1.09e-17

The fractional frequency shift for lifting an optical clock by 10 cm is $1.09 \times 10^{-17}$. This is an extremely small shift, which means that an optical clock with a precision of $10^{-18}$ could potentially detect this shift. To detect such a small shift, the clock would need to average over a long period of time to accumulate sufficient signal-to-noise ratio. The required averaging time depends on the noise characteristics of the clock and the desired sensitivity. Next step: Estimate the required averaging time based on the clock's noise characteristics and the desired sensitivity.